PHYS question!!!!!!!!

2009-01-07 1:54 am
1.A body is moving horizontally with uniform acceleration. the distance x of the body from the starting point is recorded by a camera flashing at regular intervals of 0.1s.the values of x recorded at successive flashes are 20cm ad 60cm.the acceleration of the body is?

我想問下我咁做岩唔岩?
the velocity of first 20cm(u)
=0.2/0.1
=2ms^-1
the velocity of the second part of 60cm(v)
=0.6/0.1
=6ms^-1
the acceleration of the body
=(v-u)/t
=(6-2)/0.2
=20m^-1
更新1:

terrymyh18 你做錯左...

回答 (1)

2009-01-07 4:26 am
✔ 最佳答案
You are wrong.

圖片參考:http://2uploadhk.com/upload/imgfiles/1231244271.bmp

The velocity at A:
v=s/t
v=0.2/0.1
v=2m/s
The velocity at B:
v=s/t
v=0.4/0.1
v=4m/s
v=u+at
4=2+0.1a
a=20ms-2
Firstly,the answer should measure in ms-2 not ms-1.
Secondly,your method is wrong.
參考: myself


收錄日期: 2021-04-25 23:17:34
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