how do i expand x(x-5)(x^2+x+2)?
回答 (9)
2009-01-05 3:06 pm
✔ 最佳答案
x(x-5)(x^2+x+2)=(x^2-5x)(x^2+x+2)
=x^4+x^3+2x^2-5x^3-5x^2-10x
=x^4-4x^3-3x^2-10x answer//
2009-01-05 3:18 pm
the order for expanding is:
When you have { }, [ ], or ( ) first you do whats IN { }, then whats IN [ ] and whats IN ( )
When you have *, /, -, + you do first multiplication, then division then addition then subtraction.
So in your exercise you ddon'thave { } or [ ]. And you ddon'thave multiplication or division. You just have aadditionand ssubs traction But you cant add or ssubs tractbecause you have the variable "x". Then all you have to do is multiply between parenthesis, and finally the x outside the parenthesis.
When you have { }, [ ], or ( ) first you do whats IN { }, then whats IN [ ] and whats IN ( )
When you have *, /, -, + you do first multiplication, then division then addition then subtraction.
So in your exercise you ddon'thave { } or [ ]. And you ddon'thave multiplication or division. You just have aadditionand ssubs traction But you cant add or ssubs tractbecause you have the variable "x". Then all you have to do is multiply between parenthesis, and finally the x outside the parenthesis.
2009-01-05 3:31 pm
distribute the binomial through the trinomial... we'll worry about the x later.
x²(x-5) + x(x-5) + 2(x-5)
x³ - 5x² + x² - 5x + 2x - 10
x³ - 4x² - 3x - 10
Now distribute the x
x(x³ - 4x² - 3x - 10) = x⁴ - 4x³ - 3x² - 10x
x²(x-5) + x(x-5) + 2(x-5)
x³ - 5x² + x² - 5x + 2x - 10
x³ - 4x² - 3x - 10
Now distribute the x
x(x³ - 4x² - 3x - 10) = x⁴ - 4x³ - 3x² - 10x
2009-01-05 3:24 pm
x(x-5)(x^2+x+2)
x(x^3+x^2+2x-5x^2-5x-10)
x(x^3-4x^2-3x-10)
x^4-4x^3-3x^2-10x
x(x^3+x^2+2x-5x^2-5x-10)
x(x^3-4x^2-3x-10)
x^4-4x^3-3x^2-10x
2009-01-05 3:10 pm
You just need to open the bracket & solve it.Steps are as follows-
=x(x-5)(x^2+x+2)
=(x^2-5x)(x^2+x+2)
=x^4+x^3+2x^2-5x^3-5x^2-10x
=x^4-4x^3-3x^2-10x
I hope you got it!!!!!!!!!
=x(x-5)(x^2+x+2)
=(x^2-5x)(x^2+x+2)
=x^4+x^3+2x^2-5x^3-5x^2-10x
=x^4-4x^3-3x^2-10x
I hope you got it!!!!!!!!!
2009-01-05 3:03 pm
x(x - 5)(x^2 + x + 2)
= x(x*x^2 - 5*x^2 + x*x - 5*x + x*2 - 5*2)
= x(x^3 - 5x^2 + x^2 - 5x + 2x - 10)
= x(x^3 - 4x^2 - 3x - 10)
= x^4 - 4x^3 - 3x^2 - 10x
= x(x*x^2 - 5*x^2 + x*x - 5*x + x*2 - 5*2)
= x(x^3 - 5x^2 + x^2 - 5x + 2x - 10)
= x(x^3 - 4x^2 - 3x - 10)
= x^4 - 4x^3 - 3x^2 - 10x
2009-01-05 3:02 pm
multiply it out step-by-step (forget about foiling here).
first distribute x to x-5 to yield, x^2-5x. then take that number and distribute it to x^2+x+2, to get
x^4+x^3+2x^2- 5x^3-5x^2-10x... if you combine like terms you will see your answer.
first distribute x to x-5 to yield, x^2-5x. then take that number and distribute it to x^2+x+2, to get
x^4+x^3+2x^2- 5x^3-5x^2-10x... if you combine like terms you will see your answer.
2009-01-05 3:05 pm
x ( x - 5 ) (x ^ 2 + x + 2 ) haha, how funny am I??? erm... yeah...
2009-01-05 3:03 pm
YOU APPLY THE X TO ALL WITHIN THE PARENTHESIS
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