solve the equation 15^x+1 = 29?
回答 (4)
2009-01-04 2:30 pm
✔ 最佳答案
take ln or log both sides i will take ln so
ln15^x+1=ln29
using ln & log properties the power will be multiplied
x+1(ln15)=ln29
x=[(ln29)/(ln15)]-1 =0.243
2009-01-04 10:43 pm
Do you mean :-
15^(x + 1) = 29 ????
OR
(15^x) + 1 = 29 ?????
AS WRITTEN it MUST be taken as :-
(15^x) + 1 = 29
15^x = 28
x log 15 = log 28
x = log 28 / log 15
x = 1.23
15^(x + 1) = 29 ????
OR
(15^x) + 1 = 29 ?????
AS WRITTEN it MUST be taken as :-
(15^x) + 1 = 29
15^x = 28
x log 15 = log 28
x = log 28 / log 15
x = 1.23
2009-01-04 10:42 pm
15^(x + 1) = 29
log[15^(x + 1)] = log[29]
(x + 1)log(15) = log(29)
xlog(5) + log(5) = log(29)
xlog(5) = log(29) - log(5)
xlog(5) = log(29/5)
x = log(29/5)/log(5)
log[15^(x + 1)] = log[29]
(x + 1)log(15) = log(29)
xlog(5) + log(5) = log(29)
xlog(5) = log(29) - log(5)
xlog(5) = log(29/5)
x = log(29/5)/log(5)
2009-01-04 10:27 pm
15^x=28x
x=ln(28)/ln(5)
x=1.23
x=ln(28)/ln(5)
x=1.23
收錄日期: 2021-05-01 11:49:12
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https://hk.answers.yahoo.com/question/index?qid=20090104062135AANL2Uv