Solve Log (x+2) + Log 5 = 4?

log(x+2) + log 5 = 4
log (5x + 10) = 4
5x + 10 = 10^4
x = 1998.

Tadah. Use the rules of log

to como,
as far as I know the base is generally 10 unless specified.
the answer is 1998 as boggy says.

another method (which is the longer one and from where the log rule arises):
10^(log(x+2)+log5)=10^4
10^(log(x+2))*10^(log5)=10^4
(x+2)*5=10^4
x+2=2*10^3
x=1998

Log base is not specified.
Let log be log to base 2
log [ 5 (x + 2) ] = 4
5 (x + 2) = 2^4
5x + 10 = 16
5x = 6
x = 6/5

log(x + 2) + log(5) = 4
log[5(x + 2)] = 4
log(5x + 10) = 4
5x + 10 = 10^4
5x = 10000 - 10
5x = 9990
x = 9990/5
x = 1998

Log(x+2) + log 5 = 4
log [(x +2)5] = 4
(x+2)5 = 10^4
x+2 = (10^4)/5
x+2 = 2000
x = 1998