How to simplify 4n^4 multiply 2n^-3?
2009-01-04 9:41 am
Please help me simplify the following expression. Can you please show your work so I can understand how to do this. The ^4 and ^-3 are exponents.
回答 (8)
2009-01-04 9:49 am
✔ 最佳答案
4n^4 x 2n^-3=(4*2)n^(4-3)
=8n answer
2017-01-04 11:41 pm
you will be able to desire to foil. 2x * 5x = 10x^2 2x * 3 = 6x (-3) * 5x = -15x (-3) * 3 = -9 upload 10x^2 + 6x -15x -9 = 10x^2 -9x -9 That equation could equivalent 0 you are able to remedy using quadratic formulation, if mandatory; x = (9 + 279i)/20
2009-01-04 2:08 pm
4n^4 mult 2n^-3
8n^1
8n
8n^1
8n
2009-01-04 10:19 am
4 x n^4 x 2 x n^(-3)
4 x 2 x n^4 x n^(-3)
8 n
4 x 2 x n^4 x n^(-3)
8 n
2009-01-04 9:59 am
DO YOU KNOW YOUR INDEX LAWS?
4n^4 x 2n^-3
Multiply the coefficients together. Since we have the SAME base don't we ADD the powers?
4n^4 x 2n^-3 = 8n
4n^4 x 2n^-3
Multiply the coefficients together. Since we have the SAME base don't we ADD the powers?
4n^4 x 2n^-3 = 8n
2009-01-04 9:54 am
Simply multiply the coefficients and add the indices to get 8n
2009-01-04 9:46 am
(4n^4)(2n^-3)
= (4)(2)(n^4)(n^-3)
= 8[n^(4 - 3)]
= 8[n]
= 8n
= (4)(2)(n^4)(n^-3)
= 8[n^(4 - 3)]
= 8[n]
= 8n
2009-01-04 9:46 am
(4n^4)(2n^-3) = 8n^(4-3) = 8n^1 = 8n
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