How to simplify m^4 multiply 2m^-3?

2m

m^(-3) = 1/ m^3
Therefore, 2m^(-3) = 2 / m^3
Multiply and get the answer

2 x m^4 x m^(-3)
2 m

(m^4)(2m^-3) = 2m^(4-3) = 2m^1 = 2m

(m^4)(2m^-3)
= 2[m^(4 - 3)]
= 2[m^1]
= 2m

m^4(2m^-3)
when multiplying numbers with exponents, you multiply the co-effiecients but add up the exponents........... so in this example, there are two co-effiecents 1 and 2 so that gives you 2 and the exponents are 4 and -3 so that adds up to 1, thus.......

= 2m^1.... which is the same as 2m...........enjoy.

Well, you just do this:

m^4 x 2m^-3 = 2m^1 or just 2m

you get this because it follows the exponential rule that says:

A^b x A^c = A^b+c

This applies to your question as yo have "m" as the common base, and the exponents will add up, and it will be m^4+(-3) which is equal to m^4-3, which is equal to m^1, which is the same as m, and since it has a constant in front of it, it will be 2m.

Hope this helped :D

2m

You simply add the indices to get

2m