okay so i did it just not sure
here is the problem
300=xq+n
my solution
300/q-n= xq+n/q-n
answer x= 300/q-n
is that right or wrong
thanks
ps if its wrong can u explain please
How do you solving for x ? ?
2009-01-04 8:13 am
回答 (6)
2009-01-04 8:17 am
✔ 最佳答案
300=xq+n300-n = xq
(300-n)/q=x
2009-01-04 8:25 am
your wrong.
the right solution is:
300=xq+n we transpose +n to the left
300-n=xq divide both side by q
x=(300-n)/q answer @(^_^)@
the right solution is:
300=xq+n we transpose +n to the left
300-n=xq divide both side by q
x=(300-n)/q answer @(^_^)@
2009-01-04 8:25 am
its wrong.. to solve for x.. you gotta do opposite of whats being done to it. so n is being added to it.. so the opposite is you subtract n from both sides 1st.
300-n=xq
then x is being multiplied by q.. so the opposite is you divide both sides by q 2nd.
(300-n)/q=x
theres your answer
300-n=xq
then x is being multiplied by q.. so the opposite is you divide both sides by q 2nd.
(300-n)/q=x
theres your answer
2009-01-04 10:19 am
300=xq+n
300-n=xq
(300-n)/q=x
300-n=xq
(300-n)/q=x
2009-01-04 9:04 am
300 = xq + n
xq = 300 - n
x = (300 - n)/q
xq = 300 - n
x = (300 - n)/q
2009-01-04 8:36 am
(300-n)/q=x
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