f.4 2題數學題唔識做..help!!

2009-01-05 1:24 am
http://farm2.static.flickr.com/1086/3165499213_6197e68afa.jpg?v=0
link 入面有2題數學題唔識做 幫幫手

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回答 (3)

2009-01-05 4:20 am
To b12_yi:

乜題目有話AB係直徑咩?
雖然AQ同BP係tangents,但咁唔代表AB係直徑架喎。

2009-01-04 20:29:33 補充:
To b12_yi:

乜題目有講話AB係直徑咩?
口腔AQ同BP係tangents,但並唔代表AB係直徑架喎。

2009-01-04 20:56:12 補充:
剩係睇一隻角36度一隻30度,內錯角唔相等,
已經知道AQ同BP一定唔會平行啦!

咁即係話AB一定唔係直徑,如果唔係就有矛盾。
2009-01-05 4:00 am
唔好意思,我only答到你第1條...

1. because AB⊥QA and AB⊥BP,ˉso, ∠RBP and∠RAQ is 90°,ˉˉ
ˉˉIn trangle QAR, ∠QRA=180°- 36°- 90°ˉˉ
ˉˉˉˉˉˉˉˉˉˉ so, ∠QRA=54°,ˉˉ

In trangle PBR, ∠PRB = 180° - 30° -90°
ˉˉ so, ∠PRB= 60°,ˉˉ

∠ARP = ∠BRQ (opp.∠eq.)ˉˉ
so, (360°-54°-60°)/2 = ∠ARPˉˉ
therefore, ∠ARP= 246°.ˉˉˉ
第2幅唔on scale得好緊要.....
希望你睇得明

2009-01-04 20:04:34 補充:
整得整齊d先.
1. because AB⊥QA and AB⊥BP,
so, ∠RBP and∠RAQ is 90°,
In trangle QAR, ∠QRA=180°- 36°- 90°
so, ∠QRA=54°.
In trangle PBR, ∠PRB = 180° - 30° -90°
so, ∠PRB= 60°.
∠ARP = ∠BRQ (opp.∠eq.)
so, (360°-54°-60°)/2 = ∠ARP
therefore, ∠ARP= 246°.
參考: me...


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