the sum of √-8 and 2√-50 is?

√-8 + 2√-50
= √[4*(-2)] + 2√[25*(-2)]
= √4* √-2 + 2 * √25 * √-2
= 2*√-2 + 2 * 5 * √-2 [because √4 = 2 and √25 = 5]
= 2*√-2 + 10 * √-2
= (2 + 10) *√-2
= 12 * √-2

Ans: 12 * √-2

√-8+2√-50=
√8i^2+2√50i^2=
i√8+2i√50=
i2√2+2*i*5√2=
i√2(2+10)=12i√2

√(-8) + 2√(-50)
√(-1*8) + 2√(-1*50)
√(-1*4*2) + 2√(-1*25*2)
√-1√4√2 + 2√-1√25√2
i*2√2 + 2*i*5√2
2i√2 + 10i√2
(2i + 10i)√2
12i√2

√-8 + 2√-50 = 2√-2 +2(5)√-2 = 12√-2 = 12i√2

√(-8) + 2√(-50)
= √(2^2 * i^2 * 2) + 2√(5^2 * i^2 * 2)
= 2i√2 + 2(5)(i)√2
= 2i√2 + 10i√2
= (2i + 10i)√2
= 12i√2

√-8 = 2√2 i and 2√-50 =2√(-2×5×5) =2×5√2 i= 10√2 i
√-8 + 2√-50 =2√2 i + 10√2 i= 12√2 i

2√2 i + 2(5√2) i
2√2 i + 10√2 i
12√2 i

√-8 + 2√-50
= √(8)i and 2√(50)i
= 2√(2)i and 10√(2)i
= 12√(2)i

2√2 i + 2(5√2) i
2√2 i + 10√2 i
12√2 i or √-288)

0 + 16.97i