the sum of √-8 and 2√-50 is?
回答 (11)
2009-01-03 11:57 am
✔ 最佳答案
√-8 + 2√-50= √[4*(-2)] + 2√[25*(-2)]
= √4* √-2 + 2 * √25 * √-2
= 2*√-2 + 2 * 5 * √-2 [because √4 = 2 and √25 = 5]
= 2*√-2 + 10 * √-2
= (2 + 10) *√-2
= 12 * √-2
Ans: 12 * √-2
2009-01-03 6:32 pm
â-8+2â-50=
â8i^2+2â50i^2=
iâ8+2iâ50=
i2â2+2*i*5â2=
iâ2(2+10)=12iâ2
â8i^2+2â50i^2=
iâ8+2iâ50=
i2â2+2*i*5â2=
iâ2(2+10)=12iâ2
2009-01-03 6:47 pm
â(-8) + 2â(-50)
â(-1*8) + 2â(-1*50)
â(-1*4*2) + 2â(-1*25*2)
â-1â4â2 + 2â-1â25â2
i*2â2 + 2*i*5â2
2iâ2 + 10iâ2
(2i + 10i)â2
12iâ2
â(-1*8) + 2â(-1*50)
â(-1*4*2) + 2â(-1*25*2)
â-1â4â2 + 2â-1â25â2
i*2â2 + 2*i*5â2
2iâ2 + 10iâ2
(2i + 10i)â2
12iâ2
2009-01-03 6:40 pm
â-8 + 2â-50 = 2â-2 +2(5)â-2 = 12â-2 = 12iâ2
2009-01-03 6:36 pm
â(-8) + 2â(-50)
= â(2^2 * i^2 * 2) + 2â(5^2 * i^2 * 2)
= 2iâ2 + 2(5)(i)â2
= 2iâ2 + 10iâ2
= (2i + 10i)â2
= 12iâ2
= â(2^2 * i^2 * 2) + 2â(5^2 * i^2 * 2)
= 2iâ2 + 2(5)(i)â2
= 2iâ2 + 10iâ2
= (2i + 10i)â2
= 12iâ2
2009-01-03 6:31 pm
â-8 = 2â2 i and 2â-50 =2â(-2Ã5Ã5) =2Ã5â2 i= 10â2 i
â-8 + 2â-50 =2â2 i + 10â2 i= 12â2 i
â-8 + 2â-50 =2â2 i + 10â2 i= 12â2 i
2009-01-03 6:30 pm
2â2 i + 2(5â2) i
2â2 i + 10â2 i
12â2 i
2â2 i + 10â2 i
12â2 i
2009-01-03 6:56 pm
â-8 + 2â-50
= â(8)i and 2â(50)i
= 2â(2)i and 10â(2)i
= 12â(2)i
= â(8)i and 2â(50)i
= 2â(2)i and 10â(2)i
= 12â(2)i
2009-01-03 6:34 pm
2â2 i + 2(5â2) i
2â2 i + 10â2 i
12â2 i or â-288)
2â2 i + 10â2 i
12â2 i or â-288)
2009-01-03 6:28 pm
0 + 16.97i
收錄日期: 2021-05-01 11:44:56
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090103022450AA0vwJj