If (√128 - √72) is divided by √8 the result is?

(√128 - √72)/√8
= [√(2^6 * 2) - √(3^2 * 2^2 * 2)]/√(2^2 * 2)
= [2^3√2 - 3(2)√2]/2√2
= [8√2 - 6√2]/2√2
= 8√2/2√2 - 6√2/2√2
= 4 - 3
= 1

1

√128 - √72
----------------
√8

4√8 - 3√8
---------------
√8

4 - 3

1

(√128 - √72)/√8
= (√128)/√8 - (√72)/√8
= √128/8 - √72/8
= √16 - √9
= 4 - 3
= 1

(√128 - √72)/√8=
√128 /√8 - √72/√8=
√128/8 - √72/8=
√16-√9=4-3=1

The answer is 1.
√128 = 8√2
√72 = 6√2
√8 = 2√2
in the end it is (8√2 - 6√2) / 2√2 = 2√2 / 2√2 = 1

(√128 - √72) / √8
(8√2 - 6√2) / (2√2)
(2√2)/(2√2)
= 1

Hope that helps.

=D

1