the expression (2+3i)^2 is equal to?

(2+3i)^2
=(2+3i)(2+3i) use the FOIL
=4+12i+9i^2
=4+12i+9(-1) i^2 is equivalent to =4+12i-9
=12i-5 answer @(^_^)@

(2 + 3i)^2 is the same as (2 + 3i) (2 + 3i).
This should give you 4 + 12i + 9i^2

Remember (a + b)(a + b) gives a^2 + 2ab + b^2

12i-5

-5+12i

4 + (3i)² + 12 i
4 - 9 + 12i
- 5 + 12 i

(2 + 3i)^2 = (2)^2 + (3i)^2 + 2(2)(3i)
= 4 - 9 + 12i
= -5 + 12i Answer.

-5+12i

(2 + 3i)^2
= (2 + 3i)(2 + 3i)
= 2*2 + 3i*2 + 2*3i + 3i*3i
= 4 + 6i + 6i + 9i^2
= 4 + 12i + 9(-1)
= 12i + 4 - 9
= 12i - 5

I got it and thought really hard about it and I know the answer.

The answer is
4+12i+(3i)^2

I'll prove it.
Let's say i=3
4+12(3)=40
(3*3)^2=81
81+40=121

Now watch this
(2+3*3)^2=121


-5+12(3) does not equal 121 so those can't be the answer

(2 + 3i)² = 2² + 6i + 9i² = 4 + 6i - 9 = -5 + 6i