Calculate the vapour pressure lowering (in Pa)for a solution of 8.20 g
sucrose ( C12H22O11) in 100 g water, at a temperature at which the
vapour pressure of water is 3.70kPa.
(relative atomic masses: H = 1.0, C=12.0, O=16.0)
simple vapour pressure calcu..
2009-01-02 11:25 pm
回答 (1)
2009-01-03 6:51 pm
✔ 最佳答案
Molar mass of sucrose (C12H22O11) = 12*12+ 1*22 + 16*11 = 342 g mol-1
Molar mass of water (H2O) = 1*2 + 16 = 18 g mol-1
No. of moles of sucrose = 8.2/342 = 0.0240 mol
No. of moles of water = 100/18 = 5.556 mol
Molar fraction of water, XW = 5.556/(0.0240 + 5.556) = 0.9957
Vapour pressure of pure water, PWo = 3.7 kPa = 3700 Pa
Vapour pressure of water over the solution = XWPWo = 0.9957 * 3700 = 3684 Pa
Vapour pressure lowering = 3700 - 3684 = 16 Pa
=
收錄日期: 2021-04-29 18:14:15
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090102000051KK00994