Hard math question plz help!!?
what is 1+1=?????
ii keep gtting it wrong idk why
回答 (13)
1+1= sinx-cosx+4xy-dy/dx+log6+ln(10)/1000
=5-sinx+tan/cotx+pi/3-sqrt(1000)
=∫ sinxcscx+logx-ln(100)-9
=∫ tanx(cotx)+sinx^3x-5x(3x^2+pi^2)+b
=∫pi/2+tanx-4dy/dx+1+C
=5/pi- cotx-xyz/cscx+9
=2
To solve 1+1, we must add two numbers. Let 'a' be the first number we are adding and 'b' be the second number.
So our original problem becomes:
a=1
b=1
a+b=?
From a=1 and b=1, we get a=b
Now, we multiply both sides by a
-> a^2=ab
Subtract b^2 from each side:
-> a^2-b^2=ab - b^2
Factoring:
-> (a-b)(a+b)=b(a-b)
Canceling:
-> a+b=b
Substituting for 'b' on the right:
a+b = 1
Since a+b was your original question, 1 is your answer.
there are two answers 1)2
2)11
you know what i mean and stop joking next time
Try subtracting 1 from both sides. It usually works. Failing that, add. Multiplying both sides by 1 can also be a way forward, if nothing else works.
1+1=10
There are two kinds of people in the world. Those who understand binary, and those who don't.
Under what mathematical condition are the numbers added?
In Binary system 1+1=10 while in every other number system 1+1=2.hope that help
收錄日期: 2021-05-01 11:45:13
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