(i) Expand and simplify (x-5)(x+2)(x+5)?

(x-5)(x+2)(x+5)
=(x^2-3x-10)(x+5)
=x^3-3x^2-10x+5x^2-15x-50
=x^3+2x^2-25x-50 answer @(^_^)@

= (x - 5)(x + 2)(x + 5)
= (x - 5)(x² + 5x + 2x + 10)
= (x - 5)(x² + 7x + 10)
= x³ + 7x² + 10x - 5x² - 35x - 50
= x³ + 2x² - 25x - 50

Answer: x³ + 2x² - 25x - 50

First expand the brackets seperately -8(x^2-5x+7) = -8*x^2 -8*-5x -8*7 = -8x^2 + 40x -56 5(2x-5)(3x-7) = 5(2x*3x+2x*-7-5*3x-5*-7) = 5(6x^2-14x-5x+35) = 5(6x^2-29x+35) = 30x^2-145x+175 Add the two solutions together -8x^2+40x-56+30x^2-145x+175 = 22x^2 - 105x - 119

(x - 5) (x² + 7x + 10)

x³ + 7x² + 10x - 5x² - 35x - 50

x³ + 2x² - 25x - 50

(x - 5)(x + 2)(x + 5)
= (x - 5)(x + 5)(x + 2)
= (x*x - 5*x + x*5 - 5*5)(x + 2)
= (x^2 - 5x + 5x - 25)(x + 2)
= (x^2 - 25)(x + 2)
= x^2*x - 25*x + x^2*2 - 25*2
= x^3 - 25x + 2x^2 - 50
= x^3 + 2x^2 - 25x - 50

(x^2 - 25)(x + 2)
= x^3 + 2x^2 - 25x - 50

(x-5)(x+2)(x+5)
=(x-5)(x+5)(x+2
=(x^2-25)(x+2)
=x^3+2x^2-25x-50

(x-5)(x+2)(x+5)

Just forget about the (x-5) part and expand the
(x+2)(x+5)=x²+7x+10

Then multiply that answer by (x-5)
(x²+7x+10)(x-5)
=x³+7x²+10x-5x²-35x-50
=x³+2x²-25x-50

Hope this helps

after expanding we get
x^3 + 2x^2 - 25x - 50

no simplification

= (x^2 - 25)(x + 2)
= x^3 + 2x^2 - 25x - 50