10^log8 is equal to =??
回答 (9)
2009-01-01 1:07 pm
✔ 最佳答案
Hi,10^log8 = 8 <==ANSWER
log 8 = .9031
10^,9031 = 8
In the problem above, the base of log is 10, the same a the first larger number. They, in essence, cancel each other out.
That is easier to see on the following problem:
5^(log(5)125)
If you change log(5)125 = x into exponential form, it becomes 5^x = 125. If you factor 125, this gives
5^x = 5^3, so x = 3. That means log(5)125 = 3, so the problem above becomes:
5^(log(5)125) = 5^(3) = 125
So 5 and log 5 cancel out and leave 125
I hope that helps!! :-)
2009-01-01 4:44 pm
Let log be log to base 2
10^(log 8) = 10 ³ = 1,000
10^(log 8) = 10 ³ = 1,000
2009-01-01 2:19 pm
10^[log(8)] = x
log_10(x) = log(8)
log_10(x) = log_10(8)
x = 8
log_10(x) = log(8)
log_10(x) = log_10(8)
x = 8
2009-01-01 1:30 pm
a = 10^log8
loga = log(10^log8)
loga = (log8).(log10)
loga = log8
=> a = 8
loga = log(10^log8)
loga = (log8).(log10)
loga = log8
=> a = 8
2009-01-01 1:29 pm
Let us let a variable y = 10^ log 8
then taking log both sides we get
log y = log8 *log10
log y = log8 * 1
log y = log 8
y = 8
hence, 10^log8 = 8 Answer
then taking log both sides we get
log y = log8 *log10
log y = log8 * 1
log y = log 8
y = 8
hence, 10^log8 = 8 Answer
2009-01-01 1:08 pm
100 = 10^3, so 3 is the log of 100.
So 10^log 100 = 100
And 10^log 8 just = 8
So 10^log 100 = 100
And 10^log 8 just = 8
2009-01-01 1:08 pm
Since 10 and log are inverses of each other (assuming log means log[base 10], which it usually does on most scientific calculators), they would cancel each other out, and the answer would be just 8.
2009-01-01 1:04 pm
I dunno, sounds like its time to break out the scientific calculator.
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