更新1:
I think there are some tpying mistakes,however,or rather should P^2 is even => P is even whatsoever!
Contradiction
回答 (1)
2009-01-02 1:36 am
✔ 最佳答案
if √10 is rationalThen √10=p/q where p and q are coprime
10=(p^2)/(q^2)
So p^2=10q^2=>10|p^2=>10|p
Let p=10M. Then from p^2=10q^2
100M^2=10q^2=>10M^2=q^2=>10|q^2=>10|q
And so p and q have the same factor 10, which is a contradiction
So 10^1/2 is irrational
收錄日期: 2021-04-26 13:04:39
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090101000051KK01177