✔ 最佳答案
Consider the arrow head,
object distance u = 30 cm, focal length of lens = 15 cm
hence, 1/30 + 1/v = 1/15
where v is the image distance of the arrow head
solve for v gives v = 30 cm
Consider the arrow tail,
u = (10+30) cm = 40 cm
hence, 1/40 + 1/v' = 1/15
where v' is the image distance of the arrow tail
solve for v' gives v' = 24 cm
Thus, the image of the arrow head is situated on the other side of the lens at a distance of 30 cm from it, with an image length of (30-24) cm = 6 cm.
The image is real, with the arrow pointing away fromthe lens.