Perform the indicated operations:(5x2 – 3x + 2) + (-3x2 + 9x – 8) – (x2 + 3x – 10)?

(5x2 – 3x + 2) + (-3x2 + 9x – 8) – (x2 + 3x – 10)
[– (x2 + 3x – 10) ]distribute the negative
(5x2 – 3x + 2) + (-3x2 + 9x – 8) +(– x2 -- 3x +10)
(-3x2 + 9x – 8) +(– x2 -- 3x +10) combine these two terms
(5x2 -- 3x + 2) + (-4x2 + 6x + 2)combine these two terms
x2 + 3x + 4 answer

= (5x² - 3x + 2) + (- 3x² + 9x - 8) - (x² + 3x - 10)
= 5x² - 3x + 2 - 3x² + 9x - 8 - x² - 3x + 10
= x² + 3x + 4

Answer: x² + 3x + 4

Being a math teacher I am not going to answer the question, primarily because I think you are a student! Besides, is the last set in parenthesis correct? Is it 2x or 2 times something? You simply need to follow the order of operations. For working within the parenthesis you start form the beginning of the order of operations. In the end you group by addition or subtraction all the like terms. Order of Operations: 1. Exponents 2. Everything in parenthesis 3. Multiplication and division from left to right 4. Addition and subtraction from left to right. I hope that helps. I really wouldn't want to answer until you made it clear what is going on in the third set of parentheses!

(5x^2 - 3x + 2) + (-3x^2 + 9x - 8) - (x^2 + 3x - 10)
5x^2 - 3x + 2 - 3x^2 + 9x - 8 - x^2 - 3x + 10
x^2 + 3x + 4.

group coefficients
(5x2-3x2-x2) + (-3x+9x-3x) + (2-8+10)

answer
x2 + 3x + 4

(5x2 – 3x + 2) + (-3x2 + 9x – 8) – (x2 + 3x – 10)

regroupe the alike terms

5x^2 -3x^2 - x^2 = 5x^2-4x^2 = x^2

-3x + 9x - 3x = 9x - 6x = 3x

2 - 8 +10 = 4

Answer is x^2 + 3x + 4

x² + 3x + 4

CHECK
5x² - 3x + 2
-3x² + 9x - 8
-x² - 3x + 10

x² + 3x + 4

So, simplify it first.
5X2 + -3X2 IS 2X2 - x2 is just plain X2 (2X)
then -3X + 9X + 3X is 9X
so 2X + 9X is 11X
then do the others.
so 2 -8 -10 which is -16
so 11X - 16


I Think that is right

x2+9x+4

x^2 + 3x + 4