請問不定積分∫1/√(1-x^2)dx=?
回答 (1)
2008-12-31 4:07 am
✔ 最佳答案
Let x=sinθdx=cosθdθ
∫1/√(1-x^2)dx
=∫cosθ/√(1-sinθ^2)dθ
=∫cosθ/cosθ dθ
=∫ dθ
=θ+ C
=sin^-1 x + C
收錄日期: 2021-04-26 13:03:59
原文連結 [永久失效]:
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