What is y + 3 = -3(x - 6) in slope intercept form?

Slope intercept form is

y = mx + b

So just rearrange your equation to fit this form

y + 3 = -3(x-6)

y + 3 = -3x + 18

y = -3x + 18 - 3

y = -3x + 15

And there you have it!

Have a good day!

The slope-intercept type is given by utilising y = mx + c the place m is the slope and c is the y-intercept. So, to transform the given equation to the slope-intercept type, you ought to isolate y. to try this, first upload 6 to the two sides, which will supply 2y = 10x + 6 Now divide the two sides by utilising 2 with a view to get in simple terms y on the LHS. y = 5x + 3 it is the required slope-intercept type, the slope is 5 and the y-intercept is 3.

y = -3x +15

y+3=-3(x-6)
y=-3x+15
this linear equation does not pass through the origin.

y + 3 = -3(x - 6)
y + 3 = -3x + 18
y = -3x + 18 - 3
y = -3x + 15

y + 3 = - 3x + 18

y = - 3x + 15

Slope intercept form: y = mx + b where m = slope and b = y-intercept

y + 3 = -3(x - 6)
y + 3 = -3x + 18
y = -3x + 18 - 3
y = -3x + 15 ; where m = -3 and b = 15

y=-3(x-5)

This is the best method used for graphing.