how do I solve v^2-1=1(its a quadratic equation)?

v^2-1=1
v^2 = 2
v = +- sqr2

v² - 1 = 1

Get v² by itself through basic algebraic manipulation:

v² = 2

Square root everything:

√v² = √2

The squared and square root cancel out and don't forget the plus/minus sign:

v = ±√2

Note that there are two answers because it's a quadratic. A parabola would cut through the x-axis twice.

v^2 - 1 = 1
v^2 = 1 + 1
v^2 = 2
v = ±√2

v ² = 2
v = ±√2

v² - 1 = 1
v² = 2
v = ± √2

Answer: v = ± √2

v^2 - 1 = 1
v^2 = 2 Add 1 to botch sides to isolate v/
v = sqrt of 2 Do the opposite of squared and take the square root of both sides.