can someone help me solve this equation please?

Simplify first:
= ([v - 5]/v) - ([7v - 25]/11v)
= (11[v - 5] - [7v - 25])/11v
= (11v - 55 - 7v + 25)/11v
= (4v - 30)/11v

Answer: (4v - 30)/11v OR (2[2v - 15])/11v

Then compute for v:
4v/11v - 30/11v = 0
4/11 = 30/11v
4 = 30/v
4v = 30
v = 15/2 or 7 1/2

Answer: v = 15/2 or 7 1/2

Proof (plug v with 15/2):
([15/2- 5]/[15/2]) - (7[15/2- 25]/[11{15/2}) = 0
([15/2 - 10/2]/[15/2]) - ([105/2 - 50/2]/[165/2]) = 0
([5/2][2/15]) - ([55/2][2/165]) = 0
1/3 - 1/3 = 0
0 = 0

An equation requires an = sign.
What you have posted is an expression that may be simplified.

11(v - 5) - (7v - 25)
-------------------------
11 v

4v - 55 + 25
-----------------
11 v

4v - 30
----------
11 v

SHOULD this = 0 , then :-

4v - 30 = 0
v = 7.5

(v - 5)/v - (7v - 25)/11v
= (11/11)[(v - 5)/v] - (7v - 25)/11v
= 11(v - 5)/11v - (7v - 25)/11v
= (11v - 55)/11v - (7v - 25)/11v
= (11v - 55 - 7v + 25)/11v
= (4v - 30)/11v

i assume this is = 0 otherwise it is not an equation
(v-5)/v - (7v-25)/11v = 0
(v-5)/v = (7v-25)/11v
cross multiply
11v(v-5) = v(7v-25)
11v^2 - 55v = 7v^2 -25v
since it is quadratic set = to zero
4v^2 - 30v = 0
2v(v - 15)
v = 0, v = 15

It's not an equation, but you can simplify it a bit.
(v-5)/(v )- (7v-25)/11v
multiply the first term by 11
(11v-55)/11v - (7v-25)/11v
=
(4v -30) / 11v
That's the best you can do.

That's an expression, not an equation...