what is the vertex for this equation? y= I -3x + 2 I - 4 and how do you solve?

*If x<2/3 --> y=-3x+2-4=-3x-2
*If x>=2/3 --> y=3x-2 -4= 3x-6

Vertex (2/3, -4)

Saludos

Graph the equation.
Let x=-3,-2,-1,0,1,2,3
Evaluate y
The vertex is (0.666,-4)

hummm
y=1-3x+21-4
1+21-4-3x
22-4-3x
18-3x : then after this step im not certain but i think you devide 18 by 18 and devide 3 by 18 and you will get your answer.
I got x=.16

=] much love

What you wrote above is a lineal equation. I'm guessing you didn't write The exponent in the variable x, Angela K above answered correctly for a lineal one.
I'll supposed you meant to write this:

y= 1 -3x^2 + 2 I - 4
y= -3x^2+18

In which case it is the equation of a parabola which opens downwards and is symmetric with respect to the y axis, therefore the vertex is located at (0,18)

You know this by learning to graph quadratic functions and translation of functions.

ANSWER

y = |-3x + 2| - 4
The y-coordinate of the vertex is -4.

Find x.
y = |-3x + 2| - 4
-4 = |-3x + 2| - 4
-4 + 4 = |-3x + 2|
|-3x + 2| = 0
-3x + 2 = 0
-3x = -2
x = -2/-3
x = 2/3

∴ the vertex of the equation is (2/3,-4).