factor completely: 3ax² -27a?

3ax^2-27a
=3a(x^2-9)
=3a(x+3)(x-3) answer

3ax² - 27a = 0
3ax² = 27a
ax² = 9a
x² = 9
x = +/- 3

Answer: x = 3, - 3

Proof (x = 3 or - 3):
3a(- 3²) = 27a
3a(9) = 27a
27a = 27a

3a(x^2-9)
3a(x-3)(x+3)
because we have formula (a+b)(a-b)=a^2+b^2

that is incredibly a distinction of cubes. 27 is incredibly 3 cubed and sixty 4 is 4 cubed. with a bit of luck, the a^3 and b^3 are self-explanatory. In factored type, it may be (3a - 4b)(9a^2 + 12ab + 16b^2)

3ax^2-27a

3a(x^2-9)
3a(x-3)(x+3)

a^2 - b^2 = (a + b)(a - b)

3ax^2 - 27a
= 3(ax^2 - 27a)
= 3a(x^2 - 9)
= 3a(x^2 - 3^2)
= 3a(x + 3)(x - 3)

simplify first take out 3a which would get you:

x^2 - 9.....factor this and you get (x+3)(x-3)

answer = 3a(x+3)(x-3)

3a ( x ² - 9 )

3a ( x - 3 ) ( x + 3 )

x = sqrt(9)
x = +-3

3ax² -27a = 3a(x² - 9) = 3a(a + 3)(a - 3)