factor completely: 3ax² -27a?
回答 (10)
2008-12-27 4:34 pm
✔ 最佳答案
3ax^2-27a=3a(x^2-9)
=3a(x+3)(x-3) answer
2008-12-27 4:33 pm
3ax² - 27a = 0
3ax² = 27a
ax² = 9a
x² = 9
x = +/- 3
Answer: x = 3, - 3
Proof (x = 3 or - 3):
3a(- 3²) = 27a
3a(9) = 27a
27a = 27a
3ax² = 27a
ax² = 9a
x² = 9
x = +/- 3
Answer: x = 3, - 3
Proof (x = 3 or - 3):
3a(- 3²) = 27a
3a(9) = 27a
27a = 27a
2008-12-27 4:22 pm
3a(x^2-9)
3a(x-3)(x+3)
because we have formula (a+b)(a-b)=a^2+b^2
3a(x-3)(x+3)
because we have formula (a+b)(a-b)=a^2+b^2
2016-12-11 9:04 pm
that is incredibly a distinction of cubes. 27 is incredibly 3 cubed and sixty 4 is 4 cubed. with a bit of luck, the a^3 and b^3 are self-explanatory. In factored type, it may be (3a - 4b)(9a^2 + 12ab + 16b^2)
2008-12-27 4:52 pm
3ax^2-27a
3a(x^2-9)
3a(x-3)(x+3)
3a(x^2-9)
3a(x-3)(x+3)
2008-12-27 4:36 pm
a^2 - b^2 = (a + b)(a - b)
3ax^2 - 27a
= 3(ax^2 - 27a)
= 3a(x^2 - 9)
= 3a(x^2 - 3^2)
= 3a(x + 3)(x - 3)
3ax^2 - 27a
= 3(ax^2 - 27a)
= 3a(x^2 - 9)
= 3a(x^2 - 3^2)
= 3a(x + 3)(x - 3)
2008-12-27 4:30 pm
simplify first take out 3a which would get you:
x^2 - 9.....factor this and you get (x+3)(x-3)
answer = 3a(x+3)(x-3)
x^2 - 9.....factor this and you get (x+3)(x-3)
answer = 3a(x+3)(x-3)
2008-12-27 4:27 pm
3a ( x ² - 9 )
3a ( x - 3 ) ( x + 3 )
3a ( x - 3 ) ( x + 3 )
2008-12-27 4:22 pm
x = sqrt(9)
x = +-3
x = +-3
2008-12-27 4:22 pm
3ax² -27a = 3a(x² - 9) = 3a(a + 3)(a - 3)
收錄日期: 2021-05-01 11:45:45
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20081227081728AAdcIkB