一條關於Reacting Masses的簡單化學問題
2008-12-26 3:29 am
1. The following flow diagram shows the stages involved in the extraction of lead from galena, lead (II) sulphide.
Stage I Stage II
Lead (II) sulphide →→→→→ Lead (II) oxide →→→→→ Lead
(a) Write chemical equations for the reactions involved in the extraction of lead from lead (II) sulphide.(2 marks)
(b) 337g of lead (II) sulphide are heated to produce lead (II) oxide. What is the mass of lead (II) oxides obtained? (3 marks)
回答 (1)
2008-12-26 4:01 am
✔ 最佳答案
(a)2PbS(s) + 3O2(g) → 2PbO(s) + 2SO2(g)
2PbO(s) + C(s) → 2Pb(s) + CO2(g)
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(b)
Molar mass of PbS = 207.2 + 32.1 = 239.3 g mol-1
Molar mass of PbO = 207.2 + 16 = 223.2 g mol-1
2PbS(s) + 3O2(g) → 2PbO(s) + 2SO2(g)
Mole ratio PbS : PbO = 2 : 2 = 1 : 1
No. of moles of PbS = mass/(molar mass) = 337/239.2 = 1.409 mol
No. of moles of PbO = mol x (molar mass) = 1.409 mol
Mass of PbO = 1.409 x 223.2 = 314.5 g
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