唔該寫埋條式
p[p(3pq+3q-1)-3q-1]+1
更新1:
2 ) x*2 -2x-2y+y*2+2xy+1 ( *2 姐係2次 )
更新2:
2 ) x*2 -2x-2y+y*2+2xy+1 ( *2 姐係2次 ) 呢條 個ans 可唔可以係 ( x+y)(x+y-1) ********
數學問題 因式分解
回答 (3)
2008-12-25 5:56 pm
✔ 最佳答案
=3p^3q + 3p^2q - p^2 - 3pq - p + 1= 3pq(p^2 + p - 1) - (p^2 + p - 1)
= (p^2 + p - 1)(3pq - 1).
2008-12-25 10:03:20 補充：
=(x + y)^2 - 2(x +y) + 1
= [(x + y) - 1]^2
= (x + y - 1)^2.
2008-12-25 11:53:16 補充：
Answer cannot be (x +y)(x +y -1), when you expand this, you cannot get the term +1.
2008-12-25 5:50 pm
呢題因式分解唔到<<唔知係唔係~
不過我記得我以前都做過呢題，係做唔到€
不過我記得我以前都做過呢題，係做唔到€
2008-12-25 5:42 pm
QUICk! =)
2008-12-25 09:56:59 補充：
fast !
2008-12-25 09:56:59 補充：
fast !
收錄日期: 2021-04-25 22:36:55
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20081225000051KK00263