How do you do this?
x^[(u^2) - 3]
-----------------
x^(u-3)
btw, just to clarify, I used the ------- as a fraction bar thing.
also, what do you call the fraction bar thing?
Sorry, I haven't had maths in 4 years.
Gosh! I thought I had it already!?
2008-12-24 11:52 am
回答 (5)
2008-12-24 12:01 pm
✔ 最佳答案
x^(u^2 - 3)/x^(u - 3)= x^[(u^2 - 3) - (u - 3)]
= x^(u^2 - 3 - u + 3)
= x^(u^2 - u)
We call the "fraction bar thing" as a "vinculum".
2008-12-24 8:04 pm
x^{ u^2 - 3 }
-----------------
x^(u - 3)
= x^{ (u^2 - 3) - (u - 3) }
= x^{u^2 - 3 - u + 3}
= x^{u^2 - u)
= x^[ u(u - 1) ]
The horizontal line is called a solidus.
Upper part of a fraction is called numerator.
Bottom part of a fraction is called denominator.
-----------------
x^(u - 3)
= x^{ (u^2 - 3) - (u - 3) }
= x^{u^2 - 3 - u + 3}
= x^{u^2 - u)
= x^[ u(u - 1) ]
The horizontal line is called a solidus.
Upper part of a fraction is called numerator.
Bottom part of a fraction is called denominator.
2008-12-24 8:04 pm
x^[u^2-3]-u+3=x^(u^2-u)=x^u(u-1)
2008-12-24 8:02 pm
x^(u^2-3-u+3)=x^(u^2-u)
2008-12-24 8:02 pm
when you divide powers, you substract the exponents
x^a/x^b=x^(a-b)
so the result is
x^(u^2-u) as u^2-3 -(u-3)=u^2-u
x^a/x^b=x^(a-b)
so the result is
x^(u^2-u) as u^2-3 -(u-3)=u^2-u
收錄日期: 2021-05-01 11:43:03
原文連結 [永久失效]:
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