Maths!!!

(a)
John's weight
= 60 kg (1 sig. fig.)

=====
(b)
Absolute error
= (60 - 56.6) kg
= +3.4 kg

=====
(c)
Percentage error
= (+3.4/56.6) x 100%
= +6.0% (2 sig. figs.)
=

The weight of John is 56.6kg.
(a)Find his weight (correct to 1 significant figure , unit : kg)
56.6kg=60kg,cor. to 1 sig. fig.
(b)Find the absolute error of the approximate value in (a)? (unit : kg)
(60-56.6)kg=3.4kg
(c)What is percentage error of the approximate value in (a)? (Give the answer correct to 2 significant figures)
3.4/56.6kg x 100%=6.01%,cor. to 2 sig. fig.