Simplify:√[121x12y16z6]?

√[121x12y16z6]
=11x^6y^8z^3 answer @(^_^)@

Guessing that you mean :-
√ [121 x^(12) y^(16) z^(6) ]
11 x^6 y^8 z^3

√(121x^12y^16z^6)
= √(11x^6y^8z^3)^2
= 11x^6y^8z^3

√[121x*12y*16z*6] I think is what you're saying from the question

so...break that apart and you get these seperately:
√[121] * √[x] * √[12] * √[y] * √[16] * √[z] * √[6]

simplify each individually and you get

√[121] = 11
√[x] = √[x]
√[12] = √[4] * √[3] = 2√[3]
√[y] = √[y]
√[16] = 4
√[z] = √[z]
√[6] = √[6]

now put all them all back together and you get
11*4√[3*6*x*y*z]

simplify and you finally get

44√[18xyz]

agh but you're not done yet. seems like root 18 can be a further simplified surd which is 3√[2] so...take that 3 and multiply it with 44 and keep the 2 inside the square root and you get

132√[2xyz]

Assuming z6 = z^6

= 11*2*4*z^3 √ 3xy

= 88z^3 √ 3xy

that's what school is for I suggest you pay attention!

square root the whole numbers and divide the exponents by 2 (the radicand)
√[121x12y16z6] = 11 x^6 y^8 z^3