simplify (16x^12)^3/4?
回答 (12)
2008-12-20 10:58 am
✔ 最佳答案
(16x^12)^3/4=16^(3/4) x^(12*3/4)
8x^9 (answer)
2008-12-20 7:07 pm
16x^12)^3/4
(2^4)^3/4(x^12)^3/4
(2^3)(x^9)
8x^9
(2^4)^3/4(x^12)^3/4
(2^3)(x^9)
8x^9
2008-12-20 6:56 pm
(16x^12)^3/4 = (2^4)^3/4(x^12)^3/4 = (2^3)(x^9) = 8x^9
2008-12-20 7:56 pm
(16x^12)^3/4
(16)^(3/4) * (x^12)^(3/4)
--- 8 ------ * ----- X^9
8(X^9)
(16)^(3/4) * (x^12)^(3/4)
--- 8 ------ * ----- X^9
8(X^9)
2008-12-20 7:52 pm
(16x^12)^3/4 = (2^4)^3/4(x^12)^3/4 = (2^3)(x^9) = 8x^9
2008-12-20 7:27 pm
16^(3/4) (x^12)^(3/4)
( 2 ³ ) (x³) ³
8 ( x^9 )
( 2 ³ ) (x³) ³
8 ( x^9 )
2008-12-20 7:21 pm
well according to my interpretation of this question i think it is
{16 (x)raise to power 12} whole raise to power 3/4
now
to take the power outside the power of x and 16 needs to be same
so we can write 16 = 2^4 and x^12 = x^4*3
we get on taking power 4 outside
(2x^3)^ 3/4*4
= (2x^3)^3
=8x^9
this is the answer
{16 (x)raise to power 12} whole raise to power 3/4
now
to take the power outside the power of x and 16 needs to be same
so we can write 16 = 2^4 and x^12 = x^4*3
we get on taking power 4 outside
(2x^3)^ 3/4*4
= (2x^3)^3
=8x^9
this is the answer
2008-12-20 7:02 pm
(16x^12)^3/4
The rule is multiply the indices together.
First note that 16 = 2^4
Hence
(2^4*x^12)^3/4 =
(2^3*x^9) =
8x^9
The rule is multiply the indices together.
First note that 16 = 2^4
Hence
(2^4*x^12)^3/4 =
(2^3*x^9) =
8x^9
2008-12-20 9:30 pm
(16x^12)^(3/4)
= 16^(3/4)x^(12 * 3/4)
= ⁴â(16^3)x^(3 * 3)
= ⁴â[(2^3)^4]x^9
= 2^3x^9
= 8x^9
= 16^(3/4)x^(12 * 3/4)
= ⁴â(16^3)x^(3 * 3)
= ⁴â[(2^3)^4]x^9
= 2^3x^9
= 8x^9
2008-12-20 8:42 pm
= (16x^12)^3/4
= (16^3/4)x(x^12)^3/4
= ((2^4)^3/4)x(x^3)^3
= (2^3)x(x^9)
= 8x^9
= (16^3/4)x(x^12)^3/4
= ((2^4)^3/4)x(x^3)^3
= (2^3)x(x^9)
= 8x^9
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