8個數字, 以6個為一組, 有邊28個組合?

2008-12-20 11:54 pm
8個數字, e. g. 1, 2, 3, 4, 5 ,6, 7 ,8, 以6個為一組, 會有28個組合, 咁會有邊28個??

回答 (2)

2008-12-21 1:00 am
✔ 最佳答案

28 個數字組合如下:

1: 1, 2, 3, 4, 5, 6 (缺 7, 8)
2: 1, 2, 3, 4, 5, 7 (缺 6, 8)
3: 1, 2, 3, 4, 6, 7 (缺 5, 8)
4: 1, 2, 3, 5, 6, 7 (缺 4, 8)
5: 1, 2, 4, 5, 6, 7 (缺 3, 8)

6: 1, 3, 4, 5, 6, 7 (缺 2, 8)
7: 2, 3, 4, 5, 6, 7 (缺 1, 8)
8: 1, 2, 3, 4, 5, 8 (缺 6, 7)
9: 1, 2, 3, 4, 6, 8 (缺 5, 7)
10: 1, 2, 3, 5, 6, 8 (缺 4, 7)

11: 1, 2, 4, 5, 6, 8 (缺 3, 7)
12: 1, 3, 4, 5, 6, 8 (缺 2, 7)
13: 2, 3, 4, 5, 6, 8 (缺 1, 7)
14: 1, 2, 3, 4, 7, 8 (缺 5, 6)
15: 1, 2, 3, 5, 7, 8 (缺 4, 6)

16: 1, 2, 4, 5, 7, 8 (缺 3, 6)
17: 1, 3, 4, 5, 7, 8 (缺 2, 6)
18: 2, 3, 4, 5, 7, 8 (缺 1, 6)
19: 1, 2, 3, 6, 7, 8 (缺 4, 5)
20: 1, 2, 4, 6, 7, 8 (缺 3, 5)

21: 1, 3, 4, 6, 7, 8 (缺 2, 5)
22: 2, 3, 4, 6, 7, 8 (缺 1, 5)
23: 1, 2, 5, 6, 7, 8 (缺 3, 4)
24: 1, 3, 5, 6, 7, 8 (缺 2, 4)
25: 2, 3, 5, 6, 7, 8 (缺 1, 4)

26: 1, 4, 5, 6, 7, 8 (缺 2, 3)
27: 2, 4, 5, 6, 7, 8 (缺 1, 3)
28: 3, 4, 5, 6, 7, 8 (缺 1, 2)
=
2008-12-21 1:52 am
without 1,2 : 3,4,5,6,7,8
without 1,3 : 2,4,5,6,7,8
without 1,4 : 2,3,5,6,7,8
without 1,5 : 2,3,4,6,7,8
without 1,6 : 2,3,4,5,7,8
without 1,7 : 2,3,4,5,6,8
without 1,8 : 2,3,4,5,6,7
without 2,3 : 1,4,5,6,7,8
without 2,4 : 1,3,5,6,7,8
without 2,5 : 1,3,4,6,7,8
without 2,6 : 1,3,4,5,7,8
without 2,7 : 1,3,4,5,6,8
without 2,8 : 1,3,4,5,6,7
without 3,4 : 1,2,5,6,7,8
without 3,5 : 1,2,4,6,7,8
without 3,6 : 1,2,4,5,7,8
without 3,7 : 1,2,4,5,6,8
without 3,8 : 1,2,4,5,6,7
without 4,5 : 1,2,3,6,7,8
without 4,6 : 1,2,3,5,7,8
without 4,7 : 1,2,3,5,6,8
without 4,8 : 1,2,3,5,6,7
without 5,6 : 1,2,3,4,7,8
without 5,7 : 1,2,3,4,6,8
without 5,8 : 1,2,3,4,6,7
without 6,7 : 1,2,3,4,5,8
without 6,8 : 1,2,3,4,5,7
without 7,8 : 1,2,3,4,5,6

total : 28
參考: me


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