What is (a + b + 4)^2? Please help?

(a + b + 4)^2
= (a + b + 4)(a + b + 4)
= a*a + b*a + 4*a + a*b + b*b + 4*b + a*4 + b*4 + 4*4
= a^2 + ab + 4a + ab + b^2 + 4b + 4a + 4b + 16
= a^2 + 4a + 4a + ab + ab + b^2 + 4b + 4b + 16
= a^2 + 8a + 2ab + b^2 + 8b + 16

(a + b + 4) (a + b + 4)

a² + ab + 4a
____ab_____ b² + 4b
________4a_____4b + 16

a² + 2ab + 8a + b² + 8b + 16

(a+b+4) * (a+b+4)=
a^2+ab+4a+
ab+ b^2+4b+
4a+ 4b+16=
a^2+2ab+8a+b^2+8b+16

(a+b+4)^2 means (a+b+4) is multipied by itself once.
It can also be expressed as
a^2+b^2+2ab+8a+8b+16

(a+b+4)^2 = (a+b+4)(a+b+4)
= (a^2+ab+4a+ab+b^2+4b+4a+4b+16)
=a^2+b^2 +2ab+8a+8b+16

(a +b +4)^2=

a(a+b+4) + b(a+b+4) + 4(a+b+4)
= a^2+ ab + 4a + ab + b^2 + 4b + 4a + 4b + 16=
= a^2 + b^2 + 2ab + 8b + 8a + 16

a2+b2+16

16+ab^2

(a + b + 4)(a + b + 4) =
a^2 + ab + 4a + ab + b^2 + 4b + 4a + 4b + 16 =
a^2 + 2ab + 8a + 8b + b^2 + 16

a2 + b2 + 16 + 2ab + 8a + 8b