naturally occuring bromine(relative atomic mass=79.9) consists of a mixture of only two isotopes:Br(mss number 79) and Br(mas number 81).Calculate the percentage abundance of the two isotopes in natural bromine.
Let X% and Y% be the abundance of Br(mass number79) and Br(mass number 81) respectively.
(79)(X%) + (81)(Y%) =79.9 ...
跟住應該點計牙?
chem question
2008-12-20 6:28 am
回答 (1)
2008-12-20 6:36 am
✔ 最佳答案
because you already know that it is a mixture of 2 isotopesso,
X%+Y%=100
(79)(X%)+(81)(1-X%)=79.9
-2X%=-1.1
X=55%
收錄日期: 2021-04-21 14:00:58
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20081219000051KK01561