A problem of reaction rate

1.temp increase, both reaction rates increase.

use k=A(exp)-Ea/RT, rate constant should increase at elevated temp.


so backward rate is higher. as the activation energy is lower.

2. the increase should be the same. you know rate=k{A}{B}
if there is no incrase in reactant concentration, the rate is dependent
on rate constant. I advise you to substitute some numbers to T1 to
check.


rate=k{A}{B}
and k=A(exp)-Ea/RT

then rate= A(exp)-Ea/RT *{A}*{B}