A line has equation 3x+5y=12.?

3x + 5y = 12
5y = 12 - 3x
y = 12/5 - 3x/5

The gradient is -3/5
The y intercept is 12/5
The x intercept is 4

gradient:

3x + 5y = 12
5y = 12 - 3x
y = (12 - 3x)/5
y = 12/5 - 3x/5

gradient: -3/5 (-0.8)

= = = = = = = =

y-intercept:

3x + 5y = 12
5y = 12 - 3x
y = (12 - 3x)/5

Let x = 0:
y = (12 - 3x)/5
y = (12 - 3*0)/5
y = 12/5 (2.4)

= = = = = = = =

x-intercept:

3x + 5y = 12
3x = 12 - 5y
x = (12 - 5y)/3

Let y = 0:
x = (12 - 5y)/3
x = 12/3 - 5(0)/3
x = 4

3x 5y 12

3x + 5y - 12 = 0 ( This is in the form Ax + By + C = 0 ) slope = - A / B

The gradient is:
3x + 5y = 12 ............................[1]
5y = -3x + 12
y = -3x/5 + 12/5

Therefore gradient is: -3 / 5 Answer.
For crossing the axes : For y = 0 in eqn[1] x = 4,
therefore it crosses the y-axis at point (4, 0)

For x = 0, in eqn[1] y = 12/5 = 2.4
therefore the line crosses the x-axis at point (0, 2.4)
Thus (4, 0) and (0, 2.4) Answer.

3X+5Y=12

=> Y= (-3/5)X + 12/5

So the gradient is (-3/5)

3X + 5Y = 12

=> 3X/12+ 5Y/12=1

=> X/4+ Y/(12⁄5)=1

therefore it crosses the X and Y axis at ( 4 , 0 ) and ( 0 , 12/5 ) respectibly ..

Hi there

The way I would do it is to get it in a form y = ?x + c so

subtract 3x from both sides and we get

5y = -3x + 12..Now divide both sides by 5

y = (-3/5)x + 12/5

In this form the x value (-3/5) is the slope or gradient and the 12/5 is the point that the line crosses the y-axis

To find out where it crosses the x axis make the equation

0 = (-3/5)x + 12/5

subtract 12/5 from both sides

-12/5 = (-3/5)x

now we want to divide both sides by (-3/5), you will remember that to divide one fraction by another you turn the second upside down the multiply. so we get

-12/5 * -5/3 = x giving x = 60/15 so x = 4

so the line crosses the x axis at 4

Check my arithmetic, but I think it's correct

John B

to find the gradient of any line, you need to arrange in the form of y = mx + b, i.e. make y the subject. Note: m will be your gradient.

so make y the subject of 3x + 5y = 12

3x + 5y = 12
5y = 12 - 3x (subtract 3x on both sides)
y = 12/5 - (3/5)x (divide by 5 on both sides)
y = (-3/5)x + (12/5) (rearrange right hand side so it is in the form of mx + b)

therefore m = -3/5 (so the gradient is (-3/5))

to find where it crosses the axes, i.e. the intercepts:
to find the x-intercept (Let y = 0)
3x + 5y = 12
3x + 5*0 = 12
3x + 0 = 12
3x = 12
x = 4
so, when y = 0, x = 4
therefore the x-intercept is (4,0)

to find the y-intercept (Let x = 0)
3x + 5y = 12
3*0 + 5y = 12
5y = 12
y = 12/5
so, when x = 0, y = 12/5
therefore the y-intercept is (0, 12/5)

Hope that helps. :)

hello.
2/3 = y=2
7/3 = y=1
12/3 = y=0
so the gradient is -1/2.6666666
the x intercept is 4 and the y intercept is 12/5.
there you go

5y=-3x+12,m=-3/5
x=0 y=12/5
x=4 y=0