數學differentiate一問

2008-12-18 6:28 am
differentiate
y=x^9sinx
我想問下應該要點做
想要答案同解釋
更新1:

都係有少少唔明 係咪x^9當一個數 之後sin又當一個數 者係分成2組 假如y=x^9x^7 係咪y=9x^8+7x^6? 定係y=x^9 7x^6+9x^8 x^7

回答 (5)

2008-12-18 6:30 am
✔ 最佳答案
y=x^9sinx
dy/dx
=d/dx(x^9sinx)
=(x^9)d/dx(sinx)+(sinx)d/dx(x^9)
=(x^9)cosx+sinx(9x^8)
=(x^8)(xcosx+9sinx)
2008-12-23 7:05 am
兩個答案同一個人只不過係多左幾句野,,,咁無咩理由投票俾你的
2008-12-18 8:11 am
用Product Rule,即係
dy/dx=x^9 7x^6+9x^8 x^7

不過對於呢條問題,冇理由用Product Rule,
因為可以一次過整做 y=x^16用Power Rule咪得囉。
2008-12-18 6:59 am
兩個答案一樣,遲左 22 分鐘先至回答,有乜理由叫人投票俾你?
2008-12-18 6:52 am
differentiate y=x^9sinx

要differentiate "y=x^9sinx" 呢個 function 要採用 product rule

Sol: .....y=x^9sinx

.....dy/dx=(x^9) d(sinx)dx + (sinx) d(x^9)dx

.....dy/dx=(x^9) (cosx) + (sinx)(9x^(9-1))

.....dy/dx= (x^9)(cosx) + (9x^8)(sinx)...............The Answer

Therefore, differentiate "y=x^9sinx", which results in "dy/dx= (x^9)(cosx) + (9x^8)(sinx)".

Explanation: When you differentiate the function in product terms, you need to apply the "Product Rule of the Differentiation".
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