1. given that the equation 2qx² + qx -1= 0, where q is a constant, has no real roots,
(a) show that q²+ 8q < 0.
(b) hence find the set of possible values of q.
幫幫我做1 條 數學
2008-12-18 2:26 am
回答 (2)
2008-12-18 6:52 am
✔ 最佳答案
(a)∵The equation 2qx + qx -1= 0,has no real roots,
∴Δ<0
i.e. q2-4(2q)(-1)<0
q2+8q<0
(b)
q2+8q<0
q(q+8)<0
-8<q<0
2008-12-20 5:53 am
2qx² + qx -1= 0
a=2q b=q c= -1
a=2q b=q c= -1
收錄日期: 2021-04-15 00:56:44
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