75x3 + 60x2 + 9x (the numbers 3 and 2 after the x's are exponents)?

= 75x³ + 60x² + 9x

= 3x (25x² + 20x + 3)

= 3x (25x² + 15x + 5x + 3)

= 3x [5x (5x + 3) + 1 (5x + 3)]

= 3x (5x + 1) (5x + 3) ANSWER.

75x^3 + 60x^2 + 9x
= x(75x^2 + 60x + 9)
= 3x(25x^2 + 20x + 3)
= 3x(25x^2 + 15x + 5x + 3)
= 3x[(25x^2 + 15x) + (5x + 3)]
= 3x[5x(5x + 3) + 1(5x + 3)]
= 3x(5x + 3)(5x + 1)

3x(25x^2 +20x +3)=3x(5x+3)(5x+1)

i think this is finished

x (75x^2 + 60x + 9)

x(15x + 3)(5x + 3)

First factor out 3x

3x(25x^2 + 20x + 3)

= 3x(5x + 3)(5x + 1)

3x(25x^2 + 20x + 3)=3x(5x+1)(5x+3)

use the quadratic equation. google it to find the equation, it wouldn't be readable if i typed it here.