更新1:
i need to factor completely
75x3 + 60x2 + 9x (the numbers 3 and 2 after the x's are exponents)?
回答 (7)
2008-12-17 5:54 am
✔ 最佳答案
= 75x³ + 60x² + 9x= 3x (25x² + 20x + 3)
= 3x (25x² + 15x + 5x + 3)
= 3x [5x (5x + 3) + 1 (5x + 3)]
= 3x (5x + 1) (5x + 3) ANSWER.
參考: Dont Ask...
2008-12-17 6:36 am
75x^3 + 60x^2 + 9x
= x(75x^2 + 60x + 9)
= 3x(25x^2 + 20x + 3)
= 3x(25x^2 + 15x + 5x + 3)
= 3x[(25x^2 + 15x) + (5x + 3)]
= 3x[5x(5x + 3) + 1(5x + 3)]
= 3x(5x + 3)(5x + 1)
= x(75x^2 + 60x + 9)
= 3x(25x^2 + 20x + 3)
= 3x(25x^2 + 15x + 5x + 3)
= 3x[(25x^2 + 15x) + (5x + 3)]
= 3x[5x(5x + 3) + 1(5x + 3)]
= 3x(5x + 3)(5x + 1)
2008-12-17 5:58 am
3x(25x^2 +20x +3)=3x(5x+3)(5x+1)
2008-12-17 5:56 am
i think this is finished
x (75x^2 + 60x + 9)
x(15x + 3)(5x + 3)
x (75x^2 + 60x + 9)
x(15x + 3)(5x + 3)
2008-12-17 5:54 am
First factor out 3x
3x(25x^2 + 20x + 3)
= 3x(5x + 3)(5x + 1)
3x(25x^2 + 20x + 3)
= 3x(5x + 3)(5x + 1)
2008-12-17 5:51 am
3x(25x^2 + 20x + 3)=3x(5x+1)(5x+3)
2008-12-17 5:50 am
use the quadratic equation. google it to find the equation, it wouldn't be readable if i typed it here.
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