I need this work real quick...
find the domain of the function
f(x)=
1+x^2
---------
x + 5
Help quick. Algebra, find the domain of the function?
2008-12-16 3:03 pm
回答 (5)
2008-12-16 3:06 pm
✔ 最佳答案
The domain of the function is all real numbers except -5.when x+5=0 or x=-5 , f(x) is undefined.
2008-12-16 3:07 pm
domain is always "all real numbers" except 3 special conditions:
1) a logarithm can only be positive
2) a square root can only be positive
3) the denominator cannot equal zero
We have the third case here.
x + 5 =/= 0
So, x =/= -5
The domain, therefore, includes all numbers except -5
1) a logarithm can only be positive
2) a square root can only be positive
3) the denominator cannot equal zero
We have the third case here.
x + 5 =/= 0
So, x =/= -5
The domain, therefore, includes all numbers except -5
2008-12-16 3:30 pm
x can be { R-(-5)}
2008-12-16 3:20 pm
f(x) = (1 + x^2)/(x + 5)
Domain:
|x + 5| > 0
x + 5 > 0 or x + 5 < 0
x + 5 > 0
x > -5
x + 5 < 0
x < -5
Domain:
|x + 5| > 0
x + 5 > 0 or x + 5 < 0
x + 5 > 0
x > -5
x + 5 < 0
x < -5
2008-12-16 3:07 pm
X not equal -5
收錄日期: 2021-05-01 11:38:59
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