Solve the following equation for A: 2A/3 = 8+4A?

2008-12-15 2:26 pm
A. -2.4
B. 2.4
C. 1.3
D. -1.3
E. 0

Can someone please explain to me how to solve this question? I need to brush up on my math for a college entrance exam so I can get a REAL job :) :( THANK U SO MUCH

回答 (8)

2008-12-15 2:36 pm
✔ 最佳答案
2A/3=8+4A
3(2A/3)=3(8+4A) multiply both sides by 3
2A=24+12A
2A-12A=24+12A-12A subtract 12A from both sides
-10A=24
-10A/-10=24/-10 divide both sides by -10
A=-2.4

General idea is that you can add/subtract/divide/multiply both sides of equation to bring all unknowns to one side and all numbers to the other side.
Hope this helps.
2008-12-15 2:31 pm
2A/3 = 8 + 4A
2A = 3(8 + 4A)
2A = 24 + 12A
2A - 12A = 24
-10A = 24
A = 24/-10
A = -12/5 (-2.4)
(answer A)
2008-12-15 2:32 pm
2A=24+12A , -10A=24 , A=-24/10=-12/5
2016-10-17 10:32 am
2A/3 = 8 + 4A deliver 4A on different area of '=' this might make it -4A 2A/3 - 4A = 8 take LCM(that's 3) (2A- 3*4A)/3 = 8 (2A - 12 A)/3 =8 -10A = 8*3 -10A = 24 A= -24/10 A = -2.4
2008-12-15 2:36 pm
2a/3 = 8+4a
2a=3(8+4a)
2a=24+12a
a=12+6a
a-6a=12
-5a=12
a=12/5
2008-12-15 2:35 pm
Solve for A

2A/3 = 8+4A

2A= 3(8 + 4A)

2A= 24 + 12A

2A-12A= 24

-10A= 24

A= 24/-10

A= - 12/5= -2.4 or A

ANSWER
2008-12-15 2:34 pm
first of all see that the left side of the eq is in fraction while the other one is not
so change the left side into simpler form

2A/3=8+4A
2A=3*(8+4A)
2A=24+12A
24=12A-2A
24= - 10A
A= -24/10
A=-2.4
2008-12-15 2:29 pm
2.4


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