solve for an equationsolve for 2/5y+4=6?
回答 (9)
2008-12-15 8:28 am
✔ 最佳答案
2/5y+4=6[2/5y+4=6]5y LCD: 5y
2+4(5y)=6(5y)
2+20y=30y
2=30y-20y
2=10y
y=2/10 or 1/5 answer
2008-12-15 6:18 pm
2/5(y) + 4 = 6
2y/5 = 6 - 4
2y = 5(2)
y = 10/2
y = 5
2y/5 = 6 - 4
2y = 5(2)
y = 10/2
y = 5
2008-12-15 6:05 pm
(2/5)y + 4 = 6
(2/5)y = 6 - 4
(2/5)y = 2
y=2/(2/5)
then
y = (2/1)*(5/2)
y = 10/2
so
y = 5
(2/5)y = 6 - 4
(2/5)y = 2
y=2/(2/5)
then
y = (2/1)*(5/2)
y = 10/2
so
y = 5
2008-12-15 5:03 pm
2/5y + 4 = 6
2/5y + 4 - 4 = 6 - 4
2/5y = 2
2/5y * 5 = 2 * 5
2y = 10
2y/2 = 10/2
y = 5
2/5y + 4 - 4 = 6 - 4
2/5y = 2
2/5y * 5 = 2 * 5
2y = 10
2y/2 = 10/2
y = 5
2008-12-15 5:02 pm
2/5y+4=6. Collect like terms.2/5y=6-4, 2/5y=2,.Cross multiply,it will be 2=2*5y,.2=10y,.y=1/5 or 0.2..To be sure of the answer insert d ans into d eqn.2/5(0.2)+4=6
2008-12-15 4:23 pm
Should be written as :-
(2/5) y + 4 = 6
2y + 20 = 30
y = 5
PS
As given , the question could be read as
2 / (5y + 4) = 6 and I don`t think this is what you mean ?
(2/5) y + 4 = 6
2y + 20 = 30
y = 5
PS
As given , the question could be read as
2 / (5y + 4) = 6 and I don`t think this is what you mean ?
2008-12-15 4:22 pm
2/5y+4=6 (subtract 4 from both sides)
2/5y=2 (multiply both sides by 5 to get rid of fraction)
10/5y=10 (reduce)
2y=10 (divide both sides by 2)
y=5
2/5y=2 (multiply both sides by 5 to get rid of fraction)
10/5y=10 (reduce)
2y=10 (divide both sides by 2)
y=5
2008-12-15 4:22 pm
(2/5)y + 4 = 6
(2/5)y = 6 - 4
(2/5)y = 2
y = (5/2)*2
=> y = 5
(2/5)y = 6 - 4
(2/5)y = 2
y = (5/2)*2
=> y = 5
2008-12-15 4:20 pm
Minus 4
Your equation ends up being
2/5y=2
Divide both sides by 2/5
y=5
Your equation ends up being
2/5y=2
Divide both sides by 2/5
y=5
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