Add. Simplify if possible. 3u/u^2-36 + u/u-6?
回答 (2)
2008-12-13 3:05 pm
✔ 最佳答案
Question is INCORRECT.Should be :-
3u / (u² - 36) + u / (u - 6)
3u / (u - 6)(u + 6) + u / (u - 6)
3u + u (u + 6)
-------------------
(u - 6)(u + 6)
u² + 9u
---------------
(u - 6)(u + 6)
u (u + 9)
------------------
(u - 6) (u + 9)
u
---------
(u - 6)
2008-12-13 3:14 pm
3u/(u^2 - 36) + u/(u - 6)
= 3u/(u^2 + 6u - 6u - 36) + u/(u - 6)
= 3u/(u + 6)(u - 6) + u(u + 6)/(u + 6)(u - 6)
= 3u/(u + 6)(u - 6) + (u^2 + 6u)/(u + 6)(u - 6)
= (3u + u^2 + 6u)/(u + 6)(u - 6)
= (u^2 + 9u)/(u + 6)(u - 6)
= u(u + 9)/(u + 6)(u - 6)
= 3u/(u^2 + 6u - 6u - 36) + u/(u - 6)
= 3u/(u + 6)(u - 6) + u(u + 6)/(u + 6)(u - 6)
= 3u/(u + 6)(u - 6) + (u^2 + 6u)/(u + 6)(u - 6)
= (3u + u^2 + 6u)/(u + 6)(u - 6)
= (u^2 + 9u)/(u + 6)(u - 6)
= u(u + 9)/(u + 6)(u - 6)
收錄日期: 2021-05-01 11:39:15
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