Find f(-2) when f(x)=-18x^2+12x-7?
回答 (8)
2008-12-13 2:36 pm
✔ 最佳答案
ok you have to plug in the number. f(-2)=-18(-2)^2+12(-2)-7
f(-2)=-18(4)-24-7
f(-2)=-72-24-7
f(-2)=-103
hope the helped
2008-12-13 11:26 pm
f (x) = - 18 x² + 12 x - 7
f (- 2) = - 18 (4) - 24 - 7
f (- 2) = - 72 - 31
f (-2) = - 103
f (- 2) = - 18 (4) - 24 - 7
f (- 2) = - 72 - 31
f (-2) = - 103
2008-12-13 11:12 pm
Substitute -2 wherever x is in the original equation
So...
f(-2) = -18(-2)^2 + 12(-2) - 7
= -18(4) - 24 - 7
= -72 - 24 - 7 = -103
So...
f(-2) = -18(-2)^2 + 12(-2) - 7
= -18(4) - 24 - 7
= -72 - 24 - 7 = -103
參考: I am taking algebra II right now
2008-12-13 11:01 pm
f(x) = -18x^2 + 12x - 7
f(-2) = -18(-2)^2 + 12(-2) - 7
f(-2) = -18(4) + (-24) - 7
f(-2) = -72 - 24 - 7
f(-2) = -96 - 7
f(-2) = -103
f(-2) = -18(-2)^2 + 12(-2) - 7
f(-2) = -18(4) + (-24) - 7
f(-2) = -72 - 24 - 7
f(-2) = -96 - 7
f(-2) = -103
2008-12-13 10:46 pm
all you have to do is to substitute -2 to f(x)=-18x^2+12x-7
f(-2)=-18(-2)^2+12(-2)-7
= -18(4)-24-7
=-72-24-7
f(-2)=-103 answer
f(-2)=-18(-2)^2+12(-2)-7
= -18(4)-24-7
=-72-24-7
f(-2)=-103 answer
2008-12-13 10:46 pm
Hi,
Given that f(--2) = --18(--2)^2+12(--2)--7
= --72--24--7
= --103
f(--2) = --103
Given that f(--2) = --18(--2)^2+12(--2)--7
= --72--24--7
= --103
f(--2) = --103
2008-12-13 10:36 pm
sub in -2 for each x, so
f(-2) = -18(-2)^2 + 12(-2) - 7
f(-2) = -18(4) + (-24) - 7
f(-2) = -72 - 24 - 7
f(-2) = -103
f(-2) = -18(-2)^2 + 12(-2) - 7
f(-2) = -18(4) + (-24) - 7
f(-2) = -72 - 24 - 7
f(-2) = -103
參考: im good at math
2008-12-13 10:36 pm
f(x)=-18x^2+12x-7
To find f(-2), we substitute x = -2 in the above equation
f(-2) = -18*(-2)^2 + 12*(-2) - 7
= -72-24-7 = -103
To find f(-2), we substitute x = -2 in the above equation
f(-2) = -18*(-2)^2 + 12*(-2) - 7
= -72-24-7 = -103
收錄日期: 2021-05-01 11:36:39
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20081213063205AArF9uW