Solve the compound inequality.11<4/7x+7<15?

11 < 4/7x + 7 < 15

subtract all sides by 7

11 - 7 < 4/7x + 7 - 7 < 15 - 7

4 < 4/7x < 8

now multiply both sides by 7/4 which is the reciprocal of 4/7

7/4* 4 < (7/4)* 4/7x < 7/4 * 8

7 < x < 14

x<14
x>7

or

(7,14)

Should be shown as :-
11 < (4/7)x + 7 < 15
4 < (4/7) x < 8
28 < 4x < 56
7 < x < 14

11 < 4/7(x) + 7 < 15
11 - 7 < 4x/7 < 15 - 7
4 < 4x/7 < 8
4(7) < 4x < 8(7)
28 < 4x < 56
28/4 < x < 56/4
7 < x < 14

In order to solve it, first you need to deduct 7 from every expression, so it will be:

11-7<4/7x<15-7 or, in a simple way: 4<4/7x<8
Now you need to multiply every expression with 7/4, so it will be:

4*7/4<x<8*7/4 or: 7<x<14.
And that's the answer.

7<x<14