How do I solve the following algebra equation? ?

(x - y) ÷ z

All you need to do is put the values in place for x, y and z and then solve:

[(47/8) - (1/4)] ÷ 2

(45/8) ÷ 2

45/16 OR 2 13/16 ANSWER.

= (x - y)/z
= (5 7/8 - 1/4)/2
= (47/8 - 2/8)/2
= (45/8)/2
= 45/16 or 2 13/16

Answer: 2 13/16 or 2.8125

a million. x=3x-5 2x=-5 (subtract 3x - x) x=-5/2 (then divide by 2) 2.x/3=6 (multiply 3/a million that's 3) x=18 3.y/3+5=8 y/3=3 (subtract 5) y= 9 (mulltiply by 3 or 3/a million) 4.-8=2x/9 -seventy two=2x (mulitply by 9 or 9/a million) -seventy two/2=x ( divide by 2) 5.locate f(a million) for f(x)=x3+x2-a million =(a million)3+(a million)2-a million (alternative) =3+2-a million (order of operation {PEMDAS}) =4 6.A function provides the linked fee of C as 2 *(22/7) *r. locate C while r=14cm and r=70cm. -don't understand the equation with the little stars...

5 ⅞ - 1/4
-------------
2

5 ⅝
----
2

45 / 16

2 13/16

(x - y)/z
= (5 7/8 - 1/4)/2
= [(8 * 5 + 7)/8 - 2/8]/2
= [47/8 - 2/8]/2
= (45/8)/2
= (45/8)(1/2)
= 45/16
= 2 13/16

Equation: x - y / z
x = 5 7/8
y = 1/4
z=2

= 5 7/8 - 1/4 /(over) 2
= 5 7/8 - 2/8/(over) 2 - get their LCD then subtract
= 4 5/8/(over) 2
= 4 5/8(1/2) - get the reciprocal of the denominator (2/1 = 1/2)
= 4 5/16 - Answer

2.8125

(x - y) / z
= (5 7/8 - 1/4) / 2
= (5 7/8 - 2/8) / 2
= (5 5/8) / 2
= (45/8) / 2
= 45/(8 x 2)
= 45/16

(x - y)/z = ( 5 7/8 - 1/4) / 2 = (5 7/8 - 2/8) /2
= (5 5/8)/2 = (45/8)/2 = 45/16 = 2 13/16

5(7/8)-2/8=5(5/8)

5(5/8)/2



5(5/8)*1/2

45/16

2(13/16)