x-y =11 so x = y +11 replace this in first equation xy = 80 (y+11)y = 80 y 2 +11y = 80 y 2 + 11 y - 80 = 0 fixing for y, y = -16 or 5 replace in 2d equation, x - y = 11 if y = -16 then, x +16 = 11 or x = -5 or if y = 5 then x -5 = 11 or x = 16 so, there are 2 gadgets of solutions. ie x = 16 and y = 5 or x = -5 and y = -16
hi,
the solution is as follows:
x+y=2.83 let this be called equation 1
x-y=7.77 let this be called equation 2
adding equations 1 and 2 we get:
2x=2.83+7.77
=10.60
thus x=(10.60/2)
=5.30(let this be called equation A)
therefore y=2.83-x(from equation 1)
=2.83-5.30(putting the value of x from equation A )
= -(5.30-2.83)(not necessary but for your understanding)
= -2.47
simple. let x+y = 2.83 be equation 1 and x-y = 7.77 be eqn 2
subtract eqn 2 from eqn 1
x+y - (x-y) = 2.83 -7.77
opening then bracket
x+y-x+y = -4.94
+x and -x get cancelled
now 2y = -4.94
y = -4.94/2
now y = -2.47
substitute y = -2.47 in eqn 1
i.e., x -2.47 = 2.83
x= 2.83 + 2.47
x = 5.3
since x+y=2.83, you can say that x=2.83-y. Since this x is the same value in the second equation, rather than writing "x-y=7.77" you can write "2.83-y - y = 7.77". Combine the like terms:
2.83-2y=7.77
subtract 2.83 from both sides
-2y = 4.94
divide by -2
y = -2.47
Next, use the fact that "x=2.83-y" (the first thing we reasoned) to find x.