F.1數學,,急 3條

2008-12-12 7:31 am
1. 300%(16-x)=42-x
2. a+(a-2)+(a-2+10)=24
3.There are 1500 employees in an office and 1200 of them wear glassea.If 54% of the employees who wear glasses are men and 23% of the employees who do not wear glasses are men, find the total number of women in the office.



要式,,,,吾該!!!

回答 (5)

2008-12-12 7:40 am
✔ 最佳答案
1.300%(16-x)=42-x
3(16-x)=42-x
48-3x =42-x
6 =2x
x=3

2.a+(a-2)+(a-2+10)=24
a+a-2+a-2+10=24
3a+6=24
3a=18
a=6

3.Number of men that wear glasses =1200*54%
=648
number of men that don't wear glasses =300*23%
=69

Thus,total number of men are 648+69=717

2008-12-12 00:07:05 補充:
Thus ,total number of women =1500-717 =783
2008-12-13 5:51 am
1.
300%(16-x)=42-x
3(16-x)=42-x
48-3x=42-x
48-42-3x=-x
6-3x=x
6=-x+3x
6=2x
6÷2=x
3=x
x=3
∴The answer is 3.
2.
a+(a-2)+(a-2+10)=24
a+a-2+a-2+10=24
3a+6=24
3a=24-6
3a=18
a=18÷3
a=6
∴The answer is 6.
3.
The number of men who wear glasses in the office
=1200×54%
=648(men)
The number of men who don't wear glasses in the office
=(1500-1200)×23%
=300×23%
=184(men)
The total number women in the office
=1500-648-184
=668(women)
∴The total of women in the office is 668.
2008-12-13 12:26 am
1.300%(16-x)=42-x
300/100(16-x)=42-x
3(16)-3(x)=42-x
48-3x=42-x
48-42=-x+3x
6=2x
3=x
x=3

2.a+(a-2)+(a-2+10)=24
a+a-2+a-2+10=24
3a+6=24
3a=24-6
3a=18
a=6

3. No. of man:
1200(54%)+(1500-1200)(23%)
=648+69
=717
No.of woman:
1500-717
=783
參考: me=^.^=
2008-12-12 7:45 am
1. 300%(16-x) = 42 - x
3(16-x) = 42 - x
48 - 3x = 42 - x
48 - 42 = -x + 3x
6 = 2x
x = 3

2. a + (a - 2) + (a - 2 + 10) = 24
a + a - 2 + a - 2 + 10 = 24
3a + 6 = 24
3a = 24 - 6
a = 18/3
a = 6

3. The total number of women in the office
= 1200×(1-54%) + (1500-1200)(1-23%)
= 1200×46% + 300×77%
= 1200×0.46 + 300×0.77
= 552 + 231
= 783 (woman)
參考: me
2008-12-12 7:45 am
1. 300%(16-x)=42-x
3(16-x)=42-x
48-3x=42-x
2x=6
x=3//

2. a+(a-2)+(a-2+10)=24
3a+6=24
3a=18
a=6//

3
the total number of women in the office
=1500-[1200x540%+(1500-1200)x23%)
=783//



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