How long would it take for 1.50 mol of water at 100.0 *C to be converted completely into steam if heat were added at a constant rate of 19.0 J/s
Answer must be in min.
Can someone show me how to do this problem?
How long would it take for 1.50 mol of water at 100.0 *C to be converted completely into steam if heat were..?
2008-12-10 2:48 pm
回答 (8)
2008-12-10 3:13 pm
✔ 最佳答案
1.5mol water = 27glatent heat of vaporisation of water at 100°C to steam at 100°C is:
Latent heat = 2258kJ/kg
You have 27g, So heat required is 2258*27/1000 = 61kJ
Heat is supplied at 19J/sec
It will take 61000/19 = 3,210 seconds
or 53.5 minutes.
2014-12-11 5:54 am
46.0 min if the constant rate is 22.0
2016-04-23 9:38 pm
53.3 minutes
2015-11-30 3:04 am
53.5 min
2016-12-04 8:00 pm
53.3 min
2016-07-29 10:53 pm
59.6
2016-12-10 7:39 pm
i understand this submit has been published for quiet long yet i attempted the respond that lukel presented and it became no longer ideal. So I worked it out. we've H(vap) = 40.67J/g*C so q=(40.sixty seven kJ/g*C)(a million.50 mol) = sixty one.0.5 kJ (3sF) = sixty one.0 kJ (recorded fee) warmth became utilized at a relentless 20.0J/s = 0.0200 kJ/s consequently, sixty one.0.5 kJ/0.0200 kJ/s = 3050.25 s = 50.8375 min (checklist 50.8 min) or = 0.847292 hr (checklist 0.847 hr)
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