How would you solve this one logarithmn problem?

2008-12-10 7:23 am
1. t= log (base 2 ) (10,000)
更新1:

how is it 13.3?

回答 (5)

2008-12-10 7:39 am
✔ 最佳答案
u use ure calculator to find out ln 2 and ln 10,000. These are numbers. and thats how u get 13.3 as ure answer.
2008-12-10 5:33 pm
t = log_2(10000)
t = log(10000)/log(2)
t ≈ 13.2877
2008-12-10 3:51 pm
2^t = 10,000
t log 2 = log 10,000
t = log 10,000 / log 2
t = 13.3 (any log base may be used)
2008-12-10 3:32 pm
log(base-2)(10000)
log(base-2)(10^4)
4log(base-2)(10)
4((log(base-10)(10))/log(base-10)(2))
4(1/log(base-10)(2))
4/(log(base-10)(2))

Is the best I can simplify it.

EDIT: Or, murtaza's way is much, much better.
2008-12-10 3:28 pm
2^t = 10,000
tln2 = ln10,000

t = 13.3


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