✔ 最佳答案
Reaction: O2(g) + 2SO2(g) ≒ 2SO3(g) ...ΔH = -ve
a)
Increasing the temperature of the reaction vessel, the concentration of SO3 would decrease.
Explanation:
The equilibrium position is shifted to the left, because the backward reaction is endothermic. The increase in temperature would increase the rate of the endothermic reaction to a greater extent. (You may explain this by Le Chatelier principle.)
=====
b)
Decreasing the total pressure, the concentration of SO3 would decrease.
Explanation:
The equilibrium position is shifted to the left to increase the number of moles of gaseous molecules, as there are 3 moles of gaseous molecules on the left of the equation, but only 2 moles on the right.
=====
c)
Decreasing the volume of the reaction chamber, the concentration of SO3 would increase.
Explanation:
When the volume of the reaction chamber decreases, the total pressure of the system increases (according to Boyle’s law). The equilibrium position is shifted to the right to decrease the number of moles of gaseous molecules, as there are 3 moles of gaseous molecules on the left of the equation, but only 2 moles on the right.
=
